程序员手动管理内存的释放。opencv2.3中提到Mat是一个多维的密集数据数组,可以用来处理向量和矩阵、图像、直方图等等常见的多维数据。
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class CV_EXPORTS Mat { public: int flags;(Note :目前还不知道flags做什么用的) int dims; int rows,cols; uchar *data; int * refcount; ... };
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Mat(nrows, ncols, type, fillValue]); M.create(nrows, ncols, type);
例子: Mat M(7,7,CV_32FC2,Scalar(1,3)); M.create(100, 60, CV_8UC(15));
int sz[] = {100, 100, 100}; Mat bigCube(3, sz, CV_8U, Scalar:all(0));
double m[3][3] = {{a, b, c}, {d, e, f}, {g, h, i}}; Mat M = Mat(3, 3, CV_64F, m).inv();
Mat img(Size(320,240),CV_8UC3); Mat img(height, width, CV_8UC3, pixels, step);
IplImage* img = cvLoadImage("greatwave.jpg", 1); Mat mtx(img,0); // convert IplImage* -> Mat;
访问Mat的数据元素:
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Mat M; M.row(3) = M.row(3) + M.row(5) * 3; Mat M1 = M.col(1); M.col(7).copyTo(M1); Mat M; M.at<double>(i,j); M.at(uchar)(i,j); Vec3i bgr1 = M.at(Vec3b)(i,j) Vec3s bgr2 = M.at(Vec3s)(i,j) Vec3w bgr3 = M.at(Vec3w)(i,j) double sum = 0.0f; for(int row = 0; row < M.rows; row++) { const double * Mi = M.ptr<double>(row); for (int col = 0; col < M.cols; col++) sum += std::max(Mi[j], 0.); } double sum=0; MatConstIterator<double> it = M.begin<double>(), it_end = M.end<double>(); for
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